6x^2+45x+81=0

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Solution for 6x^2+45x+81=0 equation:



6x^2+45x+81=0
a = 6; b = 45; c = +81;
Δ = b2-4ac
Δ = 452-4·6·81
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-9}{2*6}=\frac{-54}{12} =-4+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+9}{2*6}=\frac{-36}{12} =-3 $

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